4x^-10x+20=3x^-4

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Solution for 4x^-10x+20=3x^-4 equation: 



4x^-10x+20=3x^-4

We move all terms to the left:

4x^-10x+20-(3x^-4)=0

We add all the numbers together, and all the variables

-6x-(3x^-4)+20=0

We get rid of parentheses

-6x-3x^+4+20=0

We add all the numbers together, and all the variables

-9x+24=0

We move all terms containing x to the left, all other terms to the right

-9x=-24

x=-24/-9

x=2+2/3

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